Skip to main content

RC Coupled Amplifier

RC Coupled Amplifier

What You will Learn

  • You will understand the design of RC coupled amplifier.
  • You will appreciate its frequency response and understand the variation of voltage gain at low and high frequencies.
  • You will understand the effect of emitter bypass capacitor (or rather the effect of current series negative feedback) on the voltage gain and frequency response of the amplifier.
  • You will understand the concept of stability of amplifier by analyzing the Nyquist plot and understand how negative feedback improves the stability.

Objectives

  • To design and implement RC coupled amplifier and to observe voltage amplification both in Qucs and on breadboard.
  • To plot its frequency response curve and to compute the bandwidth with and without feedback.
  • Design

    Let $V_{CC}=15V$, $\beta=200$ and $I_{C}=5mA$. For active region of operation, $V_{CEQ}=\frac{V_{CC}}{2}$ \begin{equation} V_{CC} =I_{C}R_{C}+V_{CEQ}+I_{E}R_{E} \end{equation} Let the voltage across $R_{E}$ be 10 % of $V_{CC}$ \begin{align} I_{C} &\approx I_{E} \end{align} So \begin{align} \nonumber R_{E} &=\frac{0.1V_{CC}}{I_{E}}\\ \nonumber & \approx \frac{0.1\times15}{5\times 10^{-3}}\\ &= 300\,\Omega \end{align} and \begin{align} \nonumber R_{C} &=\frac{V_{CC}-V_{CEQ}-I_{E}R_{E}}{I_{C}}\\ \nonumber &= \frac{15-7.5-1.5}{5\times 10^{-3}}\\ &=1.2\,k\Omega \end{align} \begin{align} \nonumber I_{B} &\approx \frac{I_{C}}{\beta}\\ \nonumber &\approx \frac{5\times 10^{-3}}{200}\\ &\approx 25\,\mu A \end{align} Assume that $10I_B$ flows through $R_1$ and $9I_B$ flows through $R_2$. \begin{eqnarray} V_{CC}\frac{R_2}{R_{1}+R_{2}}&=& V_{BE_{active}}+I_{E}R_{E} \nonumber \\ &=& 0.8+1.5\nonumber \\ &=& 2.3\,V \end{eqnarray} \begin{align}\label{ch7eq14.eps} \nonumber R_{2} &= \frac{2.3}{9I_{B}}\\ \nonumber &= \frac{2.3}{9\times 25\times 10^{-6}}\\ &\approx 10\,k\Omega \end{align} \begin{align} \nonumber R_{1} &= \frac{V_{CC}-V_{BE_{active}}-I_{E}R_{E}}{10I_{B}}\\ \nonumber &= \frac{15-2.3}{10\times 25\times 10^{-6}}\\ \nonumber &= 51\,k\Omega\\ &\approx 47\,k\Omega \end{align} Let the coupling capacitor $C_{C}$ be $10\,\mu F$ The capacitor $C_{E}$ together with $R_{E}$ acts as a high pass filter that should bypass all ac signals above $50\,$Hz. So \begin{align} \nonumber C_{E}&=\frac{1}{2\pi R_{E} 50} \\ \nonumber &=\frac{1}{2\pi\times 300\times 50}\\ &= 10\,\mu F \end{align}

    Simulation on QUCS

    The Qucs schematic for RC coupled amplifier is shown below.

    The transient simulation results in input and output waveforms, shown below.
    The ac simulation results in the frequency response shown below. Observe the midband gain, the 3-dB frequencies and the bandwidth.

    Stability of Amplifier

    In simple terms, the Nyquist criterion for stability states that an amplifier is unstable if the Nyquist plot encircles the $-1+j0$ point. The Nyquist plot is the polar plot of the gain of the amplifier against frequency. Drop a polar plot on the display window and select the gain against frequency and observe the Nyquist plot. See the Nyquist plot below.

    See if the amplifier is stable. Understand that the stability of the amplifier arises from current series negative feedback through the resistor $ R_E$. Change the value of this resistance and observe the change in the Nyquist plot.

    Observations

  • Midband voltage gain of the RC coupled amplifier = $\ldots\ldots\ldots\ldots\, dB$
  • Bandwidth of the RC coupled amplifier = $\ldots\ldots\ldots\ldots\, kHz$
  • What You Learned

    • You understood the design of RC coupled amplifier.
    • You understood the frequency response and the variation of voltage gain at low and high frequencies.
    • You understood the effect of emitter bypass capacitor (or rather the effect of current series negative feedback) on the voltage gain and frequency response of the amplifier.
    • You analyzed the Nyquist plot and understood how negative feedback improves the stability.

    Comments

    Popular posts from this blog

    RC Integrator and Differentiator using QUCS

    RC Integrator and Differentiator using QUCS Dr. Hari V S Department of Electronics and Communication College of Engineering Karunagappally What You will Learn You will understand the operation of simple integrator and differentiator circuits using QUCS You will learn the frequency response characteristics of integrator and differentiator by dint of ac simulation. Theory Differentiator is a high pass circuit that produces the time derivative of the input signal at the output. The circuit is shown below. \begin{equation} \nonumber v_{o}=I_{o}R=RC\frac{d(v_{s}-v_{o})}{dt}\\

    Generation of Signals using MATLAB/Python

    Generation of Signals using MATLAB/Python Dr. Hari V S Department of Electronics and Communication College of Engineering Karunagappally What You will Learn You will learn about various energy signals and their generation using MATLAB and python. Signal Generation using MATLAB MATLAB arrays are used to generate finite energy signals. It should be understood that the signals so generated are discrete in time and amplitude. Sinusoidal Signal Consider the sinusoidal signal $x=sin(t)$, which is nothing but a single tone, with the help of the MATLAB code below. t=linspace(0,10,5000); x=sin(t); plot(t,x); grid; The execution of the code will result in the signal, shown below. Amplitude Modulated Signal The above low frequency tone is used to modulate a sinusoidal carrier $y$ of ten times the original frequency. i.e. $y=sin(10t)$. The amplitude modulated signal $am(t)$ is obtained as \begin{equation} am(t)=x*y+y \end{equation}Su

    Voltage Divider Circuit using QUCS

    SPICE Simulation of Voltage Divider Dr. Hari V S Department of Electronics and Communication College of Engineering Karunagappally What You will Learn You will wire up a voltage divider network using QUCS You will learn to perform DC, AC and transient simulations on the developed circuit. you will learn to observe, store and export the data from the display ( .dpl ) file. Experiment Launch QUCS. Go to Components in the left pane and select the item Lumped Components . Drag and drop a resistor onto the schematic window. Right click on on to and go to Edit properties and make the resistance 1 k&#937 Right click, copy and paste this resistor twice. Connect the three resistors in series by wires, selected by pressing Cntrl+E . Go to Components in the left pane and select Sources &#8594 ac Voltage Source . Drag and drop the source onto the schematics window. Right click on the source and change